Solutions

DL-C06-C-001

prediction - target = 6 - 10 = -4

DL-C06-C-002

error = 2 - 5 = -3
squared_error = (-3)^2 = 9

DL-C06-C-003

(4 + 4 + 1) / 3 = 9 / 3 = 3

DL-C06-C-004

The true class is class 3, so p_true is the third entry: 0.7.

DL-C06-C-005

Subtract the maximum logit, 4.

[4, 1, -2] - 4 = [0, -3, -6]

The second shifted value is -3.

DL-C06-C-006

For one-of-many classification, multiclass cross-entropy is the usual first choice because it rewards assigning high probability to the true class.